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C#代码利用随机函数生成一个4*4的两位整数矩阵,在...

int[,] arr = new int[4, 4];int row,col;Random rand = new Random();int sum1 = 0;int sum2 = 0;Console.Write("随机二维数组:\n");for (row = 0; row < 4; row++){ for (col = 0; col < 4; col++) { arr[row,col]=rand.Next (10,100); Conso...

用多线程吧 string s; private string[,] GetsArr() { string[,] sArr = new string[4,4]; for (int i = 0; i

提供一个C的,不知是否可以。#include "stdio.h"#include "stdlib.h"#include "time.h"int main(void){ int a[5][5],i,j,k; srand((unsigned)time(NULL)); for(i=0;i

添加2个command控件 Dim a(5, 5) As Integer Private Sub Command1_Click() For i = 1 To 5 For j = 1 To 5 Randomize a(i, j) = Int(Rnd * 90) + 10 Print a(i, j); Next j Print Next i End Sub Private Sub Command2_Click() Max = a(1, 1) m...

For I = 1 To 3 For J = 1 To 4 Print Int(Rnd() * 51) + 20; Next J Print Next I

C#源程序: class Program { static void Main() { Random rand = new Random(); int[,] arr = new int[4, 4]; //二维矩阵(4×4) int row, col; int num; int max; //最大值 int x, y; //最大值的下标(x, y) for (row = 0; row < 4; row++) { for...

a = round(100*rand(4,4)); %生成0-100的随机4*4矩阵 a(1,:) %输出第一行 ... a(:,1) %输出第一列 ... sum([a(1,:) a(2,1) a(2,4) a(3,1) a(3,4) a(4,:)]) %求最外圈元素的和。

您好,这样的: a = round(100*rand(4,4)); %生成0-100的随机4*4矩阵 a(1,:) %输出第一行 ... a(:,1) %输出第一列 ... sum([a(1,:) a(2,1) a(2,4) a(3,1) a(3,4) a(4,:)]) %求最外圈元素的和。

用什么语言呢

using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace 随机数 { public partial class For...

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