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一道C语言编程题,数组课后作业:编程实现从键盘任...

#include void main() { int s[20],a,n=0,i,sum=0; printf("请输入20个整数:\n"); for(i=0;i

main(){int a=0;int b=0; /*a,b分别代表正整数和负整数的个数*/int n; /*n是输入的数组长度*/scanf("%d",&n);int *arr[]=new int[n]; for(int i=0;i

#includeint main(){int a[10000],i=0,j,k,l; printf("Please input numbers:"); while(scanf("%d",&k)) { if(k==-222) break; a[i]=k; i++; } for(j=0;j

这个真不会啊呵呵

#include #include int main(){ char *a[] = {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"}; int year, y; scanf("%d", &year); y = year < 0 ? year + 1: year; // 注意:没有公元0年,公元前1年紧接着公元1年 while (y < 0)...

给,已经编译运行确认: #include #include int main() { int a[11]={0}; int num; int i,j,t; printf("请输入10个数: \n"); for(i=0;i

#include void main() { int a[10]; int i,j,max,min,temp,m,n; printf("请输入十个整数\n"); for(i=0;i

int main() { int a[100],i,x,n; printf("请输入整数个数"); scanf("%d",n); printf("请输入%d个整数",n); for(i=0;i

#include "stdio.h"float aver(int (*p)[4],int n){int i;float sum=0;for (i=0; i

数组逆序输出,只要从数组最后一位向前循环输出即可。 #include int main(void) { int arr[10] = {1,2,3,4,5,6,7,8,9,10}; int i; printf("原始数组为:\n"); for(i=0;i=0;i--) printf("%d\t",arr[i]); printf("\n"); return 0;}执行结果

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